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# Find the coordinates of the point which divides the join of (-1, 7) and (4, - 3) in the ratio 2 : 3

**Solution:**

Let the coordinates of the point be P(x, y) which divides the line segment joining the points (-1, 7) and (4, - 3) in the ratio 2 : 3

Let two points be A (x₁, y₁) and B(x₂, y₂). P (x, y) divides internally the line joining A and B in the ratio m₁: m₂. Then, coordinates of P(x, y) is given by the section formula

P (x, y) = [(mx₂ + nx₁_{ }/ m + n), (my₂ + ny₁_{ }/ m + n)]

Let x₁ = - 1, y₁ = 7, x₂ = 4 and y₂ = - 3, m = 2, n = 3

By Section formula, P (x, y) = [(mx₂ + nx₁_{ }/ m + n) , (my₂ + ny₁_{ }/ m + n)] --- (1)

By substituting the values in the equation (1)

x = [2 × 4 + 3 × (- 1)] / (2 + 3) and y = [2 × (- 3) + 3 × 7] / (2 + 3)

x = (8 - 3) / 5 and y = (- 6 + 21) / 5

x = 5/5 = 1 and y = 15/5 = 3

Therefore, the coordinates of point P are (1, 3).

**☛ Check: **NCERT Solutions Class 10 Maths Chapter 7

**Video Solution:**

## Find the coordinates of the point which divides the join of (-1, 7) and (4, - 3) in the ratio 2 : 3

NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.2 Question 1

**Summary:**

The coordinates of the point which divides the join of (- 1, 7) and (4, - 3) in the ratio 2 : 3 is (1, 3).

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