# Find the coordinates of the point which divides the join of (-1, 7) and (4, - 3) in the ratio 2 : 3

**Solution:**

Let the coordinates of the point be P(x, y) which divides the line segment joining the points (-1, 7) and (4, - 3) in the ratio 2 : 3

Let two points be A (x_{1}, y_{1}) and B(x_{2}, y_{2}). P (x, y) divides internally the line joining A and B in the ratio m_{1}: m_{2}. Then, coordinates of P(x, y) is given by the section formula

P (x, y) = [mx_{2} + nx_{1 }/ m + n, my_{2} + ny_{1 }/ m + n]

Let x_{1} = - 1, y_{1} = 7, x_{2} = 4 and y_{2} = - 3

By Section formula, P (x, y) = [(mx_{2} + nx_{1 }/ m + n) , (my_{2} + ny_{1 }/ m + n)]

By substituting the values in the Equation (1)

x = 2 × 4 + 3 × (- 1) / (2 + 3) and y = 2 × (- 3) + 3 × 7 / (2 + 3)

x = (8 - 3) / 5 and y = (- 6 + 21) / 5

x = 5/5 = 1 and y = 15/5 = 3

Therefore, the coordinates of point P are (1, 3).

**Video Solution:**

## Find the coordinates of the point which divides the join of (-1, 7) and (4, - 3) in the ratio 2 : 3

### NCERT Class 10 Maths Solutions - Chapter 7 Exercise 7.2 Question 1:

Find the coordinates of the point which divides the join of (-1, 7) and (4, - 3) in the ratio 2 : 3

The coordinates of the point which divides the join of (- 1, 7) and (4, - 3) in the ratio 2 : 3 is (1, 3)