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# Find the ratio in which the line segment joining the points (- 3, 10) and (6, - 8) is divided by (- 1, 6)

**Solution:**

The coordinates of the point P(x, y) which divides the line segment joining the points A(x₁, y₁) and B(x₂, y₂), internally, in the ratio m₁: m₂ is given by the Section Formula: P(x, y) = [(mx₂ + nx₁)_{ }/ m + n, (my₂ + ny₁)_{ }/ m + n]

Let the ratio in which the line segment joining A(- 3, 10) and B(6, - 8) be divided by point C(- 1, 6) be k : 1.

By Section formula, C(x, y) = [(mx₂ + nx₁)_{ }/ m + n, (my₂ + ny₁)_{ }/ m + n]

m = k, n = 1

Therefore,

- 1 = (6k - 3) / (k + 1)

- k - 1 = 6k - 3

7k = 2

k = 2 / 7

Hence, the point C divides line segment AB in the ratio 2 : 7.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 7

**Video Solution:**

## Find the ratio in which the line segment joining the points (- 3, 10) and (6, - 8) is divided by (- 1, 6)

NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.2 Question 4

**Summary:**

The ratio in which the line segment joining the points (- 3, 10) and (6, - 8) is divided by (- 1, 6) is 2 : 7.

**☛ Related Questions:**

- Find the ratio in which the line segment joining A (1, - 5) and B (- 4, 5) is divided by the x-axis. Also, find the coordinates of the point of division.
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- Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, - 3) and B is (1, 4).
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