If p(x) = x² - 2√2x + 1, then p(2√2) is equal to
a. 0
b. 1
c. 4√2
d.8√2 + 1
Solution:
It is given that
p(x) = x² - 2√2x + 1
We have to find p(2√2)
Let us substitute x value as 2√2
p(2√2) = (2√2)² - 2√2(2√2) + 1
By further calculation
p(2√2) = 8 - 8 + 1
So we get
p(2√2) = 1
Therefore, p(2√2) is equal to 1.
✦ Try This: If p(x) = x² - 3√3x + 2, then p(3√3) is equal to
It is given that
p(x) = x² - 3√3x + 2
We have to find p(3√3)
Let us substitute x value as 3√3
p(3√3) = (3√3)² - 3√3(3√3) + 2
By further calculation
p(3√3) = 27 - 27 + 2
So we get
p(3√3) = 2
Therefore, p(3√3) is equal to 2.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.1 Problem 5
If p(x) = x² - 2√2x + 1, then p(2√2) is equal to a. 0, b. 1, c. 4√2, d. 8√2 + 1
Summary:
The standard form of a polynomial refers to writing a polynomial in the descending power of the variable. If p(x) = x² - 2√2x + 1, then p(2√2) is equal to 1
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