# In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). Find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres

**Solution:**

Given, a rectangular plot contains 5 square flower beds of side (x + 2) metres.

We have to find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres.

Considering one square flower bed,

Side = x + 2

Perimeter of square = 4(side)

= 4(x + 2)

= 4x + 8 m

Cost of fencing 100 metres = ₹50

Cost of fencing 1 metre = 50/100

= ₹1/2

Cost of fencing (4x + 8) metres = 1/2 × (4x + 8)

Taking out 2 as common,

= 1/2 × [2(2x + 4)]

Cancelling out common term,

= 2x + 4

The cost of fencing one square flower bed = ₹2x + 4

Cost of fencing 5 square flower beds = 5(2x + 4)

= ₹10x + 20

Therefore, the total cost of fencing is ₹10x + 20.

**✦ Try This:** Find the perimeter of the figure given below:

**☛ Also Check:** NCERT Solutions for Class 7 Maths Chapter 12

**NCERT Exemplar Class 7 Maths Chapter 10 Problem 82**

## In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). Find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres

**Summary:**

In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). The total cost of fencing the flower beds at the cost of ₹50 per 100 metres is ₹(10x + 20)

**☛ Related Questions:**

- A wire is (7x - 3) metres long. A length of (3x - 4) metres is cut for use. How much wire is left
- A wire is (7x - 3) metres long. A length of (3x - 4) metres is cut for use. If this left out wire is . . . .
- Rohan's mother gave him ₹3xy² and his father gave him ₹5(xy²+2). Out of this total money he spent ₹( . . . .

visual curriculum