# In Fig. 6.18, if LM || CB and LN || CD, prove that AM/AB = AN/AD

**Solution:**

As we know if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.

In ΔABC

LM || CB

AM/MB = AL/LC............ (Eq 1)

In ΔACD

LN || CD

AN/DN = AL/ LC............ (Eq 2)

From equations (1) and (2)

AM/MB = AN/DN

⇒ MB/AM = DN/AN

Adding 1 on both sides

MB/AM + 1 = DN/AN + 1

(MB + AM)/AM = (DN + AN)/AN

AB/AM = AD/AN

AM/AB = AN/AD

**Video Solution:**

## In Fig. 6.18, if LM || CB and LN || CD, prove that AM/AB = AN/AD

### Class 10 Maths NCERT Solutions - Chapter 6 Exercise 6.2 Question 3:

In Fig. 6.18, if LM || CB and LN || CD, prove that AM/AB = AN/AD

Hence proved AM/AB = AN/AD if in the above figure LM || CB and LN || CD