# In Fig. 6.20, DE || OQ and DF || OR. Show that EF || QR

**Solution:**

As we know If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.

In ΔPOQ

DE || OQ(given)

PE/EQ = PD/DO..........(1)

In DPOR

DF || OR ( given)

PF/FR = PD/DO......... (2)

From (1) & (2)

PE/EQ = PF/FR = PD/DO

PE/EQ = PF/FR

In ΔPQR

PE/EQ = PF/FR

∴ QR || EF (Converse of Basic Proportionality theorem)

**Video Solution:**

## In Fig. 6.20, DE || OQ and DF || OR. Show that EF || QR

### Class 10 Maths NCERT Solutions - Chapter 6 Exercise 6.2 Question 5:

In Fig. 6.20, DE || OQ and DF || OR. Show that EF || QR

Hence it is proved EF || QR if in the above figure DE || OQ and DF || OR