# In Fig. 6.39, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that:

(i) ΔABC ~ ΔAMP (ii) CA/PA = BC/MP

**Solution:**

(i) If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.

This is referred as AA similarity criterion for two triangles.

In ΔABC and ΔAMP

∠ABC = ∠AMP = 90º

∠BAC = ∠MAP (Common angle)

Thus, ΔABC ∼ ΔAMP (AA criteria)

(ii) As we know that the ratio of any two corresponding sides in two similar triangles is always the same,

In ΔABC and ΔAMP

CA/PA = BC/MP [∵ ΔABC ∼ ΔAMP]

**Video Solution:**

## In Fig. 6.39, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i) ΔABC ~ ΔAMP (ii) CA/PA = BC/MP

### NCERT Class 10 Maths Solutions - Chapter 6 Exercise 6.3 Question 9:

**Summary:**

In the above figure, ABC and AMP are two right triangles, right-angled at B and M respectively. Hence it is proved that ΔABC ~ ΔAMP and CA/PA = BC/MP.