D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD
In ΔABC and ΔDAC
∠BAC = ∠ADC (Given in the statement)
∠ACB = ∠ACD (Common angles)
⇒ ΔABC ∼ ΔDAC (AA criterion)
⇒ CA / CD = CB / CA
⇒ CA2 = CB × CD
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA² = CB.CD
NCERT Solutions Class 10 Maths Chapter 6 Exercise 6.3 Question 13
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. We have proved that CA2 = CB.CD.
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