# Match each of the entries in Column I with the appropriate entries in Column II

Column I Column II

(i) x + 5 = 9 (A) -5/3

(ii) x - 7 = 4 (B) 5/3

(iii) x/12 = - 5 (C) 4

(iv) 5x = 30 (D) 6

(v) The value of y which satisfies 3y = 5 (E) 11

(vi) If p = 2, then the value of 1/3 (1 - 3p) (F) -60

(G) 3

**Solution:**

Let’s solve the equations given in Column I

(i) x + 5 = 9

x = 9 - 5

x = 4

Thus, the correct option is (C)

(ii) x - 7 = 4

x = 4 + 7

x = 11

Thus, the correct option is (E)

(iii) x/12 = -5

x = -5(12)

x = -60

Thus, the correct option is (F)

(iv) 5x = 30

x = 30/5

x = 6

Thus, the correct option is (D)

(v) 3y = 5

y = 5/3

Thus, the correct option is (B)

(vi) 1/3 (1 - 3p)

= 1/3 (1 - 3.2)

= 1/3 (1 - 6)

= 1/3 (- 5)

= - 5/3

Thus, the correct option is (A)

Hence, followings are the matched appropriate entries in Column I with the Column II.

**Column I Column II**

(i) x + 5 = 9 (C) 4

(ii) x - 7 = 4 (E) 11

(iii) x/12 = - 5 (F) -60

(iv) 5x = 30 (D) 6

(v) The value of y which satisfies 3y = 5 (B) 5/3

(vi) If p = 2, then the value of 1/3 (1 - 3p) (A) -5/3

**✦ Try This:** Match each of the entries in Column I with the appropriate entries in Column II.

**Column I Column II**

(i) x + 3 = 9 (A) - 5/3

(ii) x - 3 = 8 (B) 0

(iii) x/3 = - 20 (C) 4

(iv) 4x = 24 (D) 6

(v) The value of x which satisfies 6x = - 10 (E) 11

(vi) If m = 3, then the value of 3m (3 - m) (F) -60

(G) 5/3

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 4

**NCERT Exemplar Class 7 Maths Chapter 4 Problem 56**

## Match each of the entries in Column I with the appropriate entries in Column II (i) x + 5 = 9 (A) -5/3 (ii) x - 7 = 4 (B) 5/3 (iii) x/12 = - 5 (C) 4 (iv) 5x = 30 (D) 6 (v) The value of y which satisfies 3y = 5 (E) 11 (vi) If p = 2, then the value of 1/3 (1 - 3p) (F) -60

**Summary:**

Following are the matched appropriate entries in Column I with the Column IIColumn I Column II (i) x + 5 = 9 (C) 4(ii) x - 7 = 4 (E) 11(iii) x/12 = - 5 (F) -60(iv)5x = 30 (D) 6(v) The value of y which satisfies 3y = 5 (B) 5/3(vi) If p = 2, then the value of 1/3 (1 - 3p) (A) -5/3

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