# NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.3 Surface Areas and Volumes

With the help of a simple activity of using a paper and a string, the NCERT solutions for Class 9 maths Chapter 13 exercise 13.3 Surface Areas And Volumes introduces a three-dimensional image of the right circular cone. A right-angled triangle with a string attached to one of its perpendicular sides, when rotated, forms the right circular cone. The students will easily be able to identify it with an ice cream cone.

How the formula for calculating the curved surface area of the right circular cone is obtained is derived step by step for a student's understanding. The Class 9 maths NCERT solutions Chapter 13 exercise 13.3 consists of 8 questions, 7 are easy and 1 might require some time to solve, the details of NCERT solutions for Class 9 maths Chapter 13 exercise 13.3 which can be found in the pdf below :

**ā** Download NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.3

**Exercise 13.3 Class 9 Chapter 13 **

### More Exercises in Class 9 Maths Chapter 13

- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.1
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.2
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.4
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.5
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.6
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.7
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.8
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.9

## NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.3 Formulas

The formulas for cone in the NCERT solutions Class 9 maths Chapter 13 exercise 13.2 Surface Areas And Volumes are as follows:

**Curved Surface Area of a Cone**= 1 /2 × l × 2πr = πrl,

where ‘r’ is its base radius and ‘l’ its slant height

Then, ‘l’ = Square root of (r^{2 }+ h^{2})

**Total Surface Area of a Cone = πrl + πr**^{2}= πr(l + r)

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