# NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.8 Surface Areas and Volumes

The NCERT solutions for Class 9 maths Chapter 13 exercise 13.8 Surface Areas and Volumes explains the volume of a sphere. With the help of an experiment involving a trough, a container, a sphere, and water, the students will observe that the volume of the sphere is the same as the volume of the water displaced by it. We get the same conclusion by repeating this experiment with spheres of different radii, meaning that the volume of a sphere is equal to (4 / 3) π times the cube of its radius.

The NCERT solutions Class 9 maths Chapter 13 exercise 13.8 consists of 10 questions. The details regarding the same can be found in the pdf file below:

**ā** Download NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.8

**Exercise 13.8 Class 9 Chapter 13 **

### More Exercises in Class 9 Maths Chapter 13

- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.1
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.2
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.3
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.4
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.5
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.6
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.7
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.9

## NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.8 Formulas

The volume of sphere formula stated in the NCERT solutions Class 9 maths Chapter 13 exercise 13.8 Surface Areas And Volumes is as follows:

**Volume of a Sphere = (4/3) π r**^{3}**Volume of a Hemisphere = (2/3) πr**^{3}

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