# NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.2 Surface Areas and Volumes

The NCERT Solutions for Class 9 maths Chapter 13 exercise 13.2 Surface Areas and Volumes outlines the details of a right circular cylinder so that the students get a clear understanding of what it is. This has been explained with the help of a simple activity of stacking up circular cardboard sheets and with the help of appropriate diagrams.

Further, the concept of the NCERT solutions Class 9 maths Chapter 13 exercise 13.2 surface area of a cylinder has been explained with the help of an example. If a particular sheet of paper is required to cover the cylinder, its area would give the surface area of the cylinder, wherein the length of the sheet will be equal to the circumference of the base of the cylinder (2 π r). Class 9 maths NCERT solutions Chapter 13 exercise 13.2 consists of 11 questions which are basically formula based and can be accessed through the link below :

**☛** Download NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.2

**Exercise 13.2 Class 9 Chapter 13 **

### More Exercises in Class 9 Maths Chapter 13

- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.1
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.3
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.4
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.5
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.6
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.7
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.8
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.9

## NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.2 Formulas

The relevant formulas for curved and the total surface area of a cylinder as given in the NCERT solutions Class 9 maths Chapter 13 exercise 13.2 Surface Areas And Volumes are as follows:

**Curved Surface Area of a Cylinder = 2πrh****Total Surface Area of a Cylinder = 2πr(r + h)**

These formulas will help in solving the exercise questions, hence the students must make a note of these.

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