# NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.4 Surface Areas and Volumes

The NCERT Solutions for Class 9 maths Chapter 13 exercise 13.4 Surface Areas and Volumes sheds light on the concept of the surface area of a sphere. It starts with the explanation of a circle and how a circle in three-dimension can get evolved into a sphere with the help of a circular paper and string activity.

The students will find a sphere to be similar to the surface of a ball. How the formula for calculating the curved surface area of the right circular cone is obtained is derived step by step so as to explain the topic clearly. The Class 9 maths NCERT solutions Chapter 13 exercise 13.4 consists of 8 questions; 7 are easy, while 1 might require some time to solve. The NCERT solutions Class 9 maths Chapter 13 exercise 13.4 questions can be accessed by the link below:

**☛** Download NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.4

**Exercise 13.4 Class 9 Chapter 13 **

### More Exercises in Class 9 Maths Chapter 13

- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.1
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.2
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.3
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.5
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.6
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.7
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.8
- NCERT Solutions Class 9 Maths Chapter 13 Ex 13.9

## NCERT Solutions Class 9 Maths Chapter 13 Exercise 13.4 Formulas

The formulas covered in the NCERT solutions Class 9 maths Chapter 13 exercise 13.4 Surface Areas And Volumes are given below:

**Surface Area of a Sphere = 4 π r**^{2}**Curved Surface Area of a Hemisphere = 2πr**^{ 2}**Total Surface Area of a Hemisphere = 3πr**^{ 2 }

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## Class 9 Maths NCERT Solutions Video Chapter 13 Exercise 13.4

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