# 3 bananas are to be selected from a group of 9. In how many ways can this be done?

**Solution:**

We can use combination formula to find the required number of ways.

It is given that

3 bananas are to be selected from a group of 9.

We know that formula,

^{n}C_{x} = n! / x! (n - x)!

Then, if 3 bananas are to be selected from a group of 9, then the number of ways will be,

^{9}C_{3} = 9! / (3! (9 - 3)!)

^{9}C_{3} = (9 × 8 × 7 × 6!)/((3 × 2 × 1)6!)

^{9}C_{3} = (9 × 8 × 7 × 6!)/((6 × 6!)

^{9}C_{3} = (9 × 8 × 7)/6

^{9}C_{3} = 504/6

^{9}C_{3} = 84

Therefore, this can be done in 84 ways.

## 3 bananas are to be selected from a group of 9. In how many ways can this be done?

**Summary:**

3 bananas are to be selected from a group of 9, this can be done in 84 ways.

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