# What are the values of x in the equation 4x^{2} + 4x - 3 = 0?

x = -1.5, 0.5

x = -1.5, -0.5

x = (-4 ± √-32)/8

x = (-4 ± √-64)/8

**Solution:**

Given: 4x^{2} + 4x - 3 = 0

To solve the quadratic equation,

let us group the terms which contain the same variables and move the constant to the other side

4x^{2} + 4x = 3

Add 1 on both sides

4x^{2} + 4x + 1 = 3 + 1

4x^{2} + 4x + 1 = 4

Taking out 4 and dividing both sides by 4

4(x^{2} + x + 0.25) = 4

x^{2} + x + 0.25 = 1

So we get

(x + 0.5)^{2} = 1

Squaring on both sides

x + 0.5 = ± 1

x = -0.5 ± 1

Here

x = -0.5 + 1 and x = -0.5 - 1

x = 0.5 and x = -1.5

Therefore, the values of x are 0.5 and -1.5

## What are the values of x in the equation 4x^{2} + 4x - 3 = 0?

**Summary:**

The values of x in the equation 4x^{2} + 4x - 3 = 0 are 0.5 and -1.5