# What is the 6th term of the geometric sequence where a1 = -625 and a2 = 125?

**Solution:**

The formula to find the nth term of geometric sequence is

a_{n} = a r^{n-1}

Where a1 is the first number

r is the ratio

n is the number of terms

It is given that

a = -625

r = 125/-625 = -1/5

n = 6

Substituting it in the formula

a_{6} = -625 x (-1/5)^{6-1}

By further calculation

a_{6} = -625 x (-1/5)^{5}

a_{6} = -625 x (-1/3125)

So we get

a_{6} = 1/5

a_{6} = 0.2

Therefore, the 6th term of the geometric sequence is 0.2.

## What is the 6th term of the geometric sequence where a1 = -625 and a2 = 125?

**Summary:**

The 6th term of the geometric sequence where a_{1 }= -625 and a_{2 }= 125 is 0.2.

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