# Which are factors of x^{2} - 4x - 5? Check all that apply.

(x - 5), (x - 4),(x - 2), (x + 1),(x + 5)

**Solution:**

Let us factorise the polynomial to find the value of x by splitting the middle term.

**Step 1:**

Identify the values of a, b and c.

**In the above equation, a is coefficient of x ^{2 }= 1,**

**b is the coefficient of x which is - 4 and c is the constant term = - 5.**

**Step 2: **

Multiply a and c and find the factors that add up to b.

1 × (- 5) = - 5

**⇒ - 5 and 1 are the factors that add up to b.**

**Step 3: **

**Split bx into two terms.**

x^{2} - 5x + 1x - 5 = 0

**Step 4:**

**Take out the common factors by grouping.**

x(x - 5) + 1 (x - 5) = 0

(x - 5) (x + 1) = 0

**By putting the factors equal to zero we get two values of x**

x - 5 = 0 and x + 1 = 0

x = 5 and x = - 1

**Thus, the two values that satisfy the equation are 5 and - 1.**

## Which are factors of x^{2} - 4x - 5? Check all that apply.

(x - 5), (x - 4),(x - 2), (x + 1),(x + 5)

**Summary:**

(x - 5) ( x + 1) are the solutions that apply to the equation x^{2} - 4x - 5.

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