Which equation is the inverse of 2(x - 2)² = 8(7 + y)?
-2(x - 2)² = -8(7 + y)
y = 1/4 x² -x -6
y = -2 +/- sqrt of 28 + 4x
y = 2 +/- sqrt of 28 + 4x

Solution:

The given equation is:

2(x - 2)² = 8(7 + y)

Divide both sides by 8

(x - 2)²/4 = (7 + y)

Subtract 7 from both sides

y = (x - 2)²/4 - 7

Now interchange the variables

x = (y - 2)²/4 - 7

Taking LCM

x =[(y - 2)² - 28]/4

Multiply both sides by 4

4x = (y - 2)² - 28

(y - 2)² = 4x + 28

Take square root on both sides

y - 2 = ± √(4x + 28)

y = 2 ± √(4x + 28)

Therefore, the inverse of the given equation is y = 2 ± √(4x + 28).

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Which equation is the inverse of 2(x - 2)² = 8(7 + y)?

Summary:

The inverse of 2(x - 2)² = 8(7 + y) is y = 2 ± √(4x + 28).