# 4/√3. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

**Solution:**

Given, the expression is 4/√3

We have to rationalise the denominator and evaluate the given expression.

To rationalise we have to take conjugate,

4/√3 = 4/√3 × √3/√3

= 4√3/3

Given, √3 = 1.732

4√3/3 = 4(1.732)/3

= 6.928/3

= 2.3093333

Therefore, 4/√3 = 2.309

**✦ Try This: **Rationalise the denominator of the following and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal 5/√3

Given, the expression is 5/√3

We have to rationalise the denominator and evaluate the given expression.

To rationalise we have to take conjugate,

5/√3 = 5/√3 × √3/√3

= 5√3/3

Given, √3 = 1.732

5√3/3 = 5(1.732)/3

= 8.66/3

= 2.88667

Therefore, 5/√3 = 2.887

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 1

**NCERT Exemplar Class 9 Maths Exercise 1.3 Problem 13(i)**

## 4/√3. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

**Summary:**

On rationalising the denominator and evaluating the expression 4/√3 by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, we get 2.309

**☛ Related Questions:**

- 6/√6. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236 . . . .
- (√10 - √5)/2. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 . . . .
- √2/(2 + √2). Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 . . . .

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