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# Area of triangle MNO of Fig. 9.17 is

a. 1/2 MN × NO

b. 1/2 NO × MO

c. 1/2 MN × OQ

d. 1/2 NO × OQ

**Solution:**

We know that

__Area of triangle__ = 1/2 × b × h

From the figure

Area of triangle = 1/2 × NO × OQ

Therefore, the area of the triangle MNO is 1/2 × NO × OQ.

**✦ Try This: **9 hectare = ____ cm²

We know that

1 hectare = 10,00,00,000

So we get

9 hectare = 90,00,00,000

Therefore, 9 hectare = 90,00,00,000 cm²

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 9**

## Area of triangle MNO of Fig. 9.17 is a. 1/2 MN × NO, b. 1/2 NO × MO, c. 1/2 MN × OQ, d. 1/2 NO × OQ

**Summary:**

Area of triangle MNO of Fig. 9.17 is 1/2 × NO × OQ

**☛ Related Questions:**

- Ratio of area of ∆MNO to the area of parallelogram MNOP in the same figure 9.17 is a. 2 : 3, b. 1 : . . . .
- Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in Fig. 9.18 is a. 2 : 1 : 3, b. 1 : 3 : 2, c. 2 : 3 : 1, d. 1 . . . .
- In Fig. 9.19, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4cm respectively. If EF = 10 . . . .

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