# Factorise : x² + 9x + 18

**Solution:**

Given, the __polynomial__ is x² + 9x + 18.

We have to __factorise the polynomial__.

On factoring by splitting the middle term,

x² + 9x + 18

x² + 6x + 3x + 18

x(x + 6) + 3 (x + 6)

(x + 3)(x + 6)

Therefore, the factors are (x + 3) and (x + 6).

**✦ Try This: **Factorise : x² + 6x + 8

Given, the polynomial is x² + 6x + 18.

We have to factorise the polynomial.

On factoring by splitting the middle term,

x² + 6x + 8

x² + 4x + 2x + 8

x(x + 4) + 2(x + 4)

(x + 4)(x + 2)

Therefore, the factors are (x + 4) and (x + 2).

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 23(i)**

## Factorise : x² + 9x + 18

**Summary:**

A polynomial equation is an equation formed with variables, exponents, and coefficients together with operations and an equal sign. On factoring x² + 9x + 18 the factors are (x + 3) and (x + 6)

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