# Find the equation for the ellipse that satisfies the given conditions: Foci (± 3, 0), a = 4

**Solution:**

Foci (± 3, 0), a = 4

Since the foci are on the x-axis, the major axis is along the x-axis.

Therefore,

the equation of the ellipse will be of the form x^{2}/a^{2} + y^{2}/b^{2} = 1 where a is the semi-major axis.

Accordingly,

a = 4 and c = 3.

It is known that a^{2} = b^{2} + c^{2}

Hence,

⇒ 4^{2} = b^{2} + 3^{2}

⇒ 16 = b^{2} + 9

⇒ b^{2} = √16 - 9

⇒ b = √7

Thus, the equation of the ellipse is x^{2}/4^{2} + y^{2}/(√7)^{2} = 1 or x^{2}/16 + y^{2}/7 = 1

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.3 Question 17

## Find the equation for the ellipse that satisfies the given conditions: Foci (± 3, 0), a = 4

**Summary:**

The equation of the ellipse is x^{2}/16 + y^{2}/7 = 1 while Foci is (± 3, 0) and the value of a is 4

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