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# Find the value of the polynomial 5x - 4x^{2} + 3 at

i) x = 0 ii) x = -1 iii) x = 2

**Solution:**

Let the polynomials p(x) = 5x - 4x^{2} + 3

i) p(0) = 5(0) - 4(0)^{2} + 3

= 0 - 0 + 3

= 3

ii) p(-1) = 5(-1) - 4(-1)² + 3

= -5 - 4 + 3

= -6

iii) p(2) = 5(2) - 4(2)^{2} + 3

= 10 - 16 + 3

= -3

**☛ Check: **Class 9 Maths NCERT Solutions Chapter 2

**Video Solution:**

## Find the value of the polynomial 5x - 4x² + 3 at i) x = 0 ii) x = -1 iii) x = 2

NCERT Solutions Class 9 Maths Chapter 2 Exercise 2.2 Question 1

**Summary:**

The value of the polynomial 5x − 4x² + 3 at x = 0, x = -1, and x = 2 are 3, -6, and -3 respectively.

**☛ Related Questions:**

- Find p(0), p(1) and p 2) for each of the following polynomials:(i) p(y) = y2 - y + 1(ii) p(t) = 2 + t + 2t2 - t3iii) p(x) = x3iv) p(x) = (x - 1)(x + 1)
- Verify whether the following are zeroes of the polynomial, indicated against them. (i) p(x) = 3x + 1, x = -(1/3)(ii) p(x) = 5x - π , x = 4/5(iii) p(x) = x2 - 1, x = 1, -1(iv) p(x) = (x + 1)(x - 2), x = -1, 2 (v) p(x) = x2 , x = 0(vi) p(x) = lx + m, x = -(m/l)(vii) p(x) = 3x2 - 1, x = -(1/√3), 2/√3(viii) p(x) = 2x + 1, x = 1/2
- Find the zero of the polynomials in each of the following cases:(i) p(x) = x + 5(ii) p(x) = x - 5(iii) p(x) = 2x + 5(iv) p(x) = 3x - 2(v) p(x) = 3x(vi) p(x) = ax, a ≠ 0(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.

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