If ∆ is an operation such that for integers a and b we have a ∆ b = a × a + b × b - a × b, then find (-3) ∆ 2
Solution:
In the given problem we have a ∆ b = a × a + b × b -a × b
To find the value of (-3) ∆ 2. Let us consider a = -3 and b = 2.
To evaluate the expression we need to substitute the values of a and b in a ∆ b = a × a + b × b -a × b. On substituting the values we have,
-3 ∆ 2 = (-3) × (-3) + 2 × 2 - (-3) × 2
= 9 + 4 - (-6)
= 13 + 6
= 19
Therefore, if ∆ is an operation such that for integers a and b we have a ∆ b = a × a + b × b -a × b, then the value of (-3) ∆ 2 is 19
✦ Try This: If ∆ is an operation such that for integers a and b we have a ∆ b = a + a + b × b + a × b, then find 5 ∆ 2.
Using the same logic as above and after substituting the values of a and b in a ∆ b = a + a + b × b + a × b, we can easily calculate the value of 5 ∆ 2. The final value of 5 ∆ 2 is 24.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 1
NCERT Exemplar Class 7 Maths Chapter 1 Solved Ex 15
If ∆ is an operation such that for integers a and b we have a ∆ b = a × a + b × b – a × b, then find (-3) ∆ 2
Summary:
Using the integers properties and further on evaluating the expression a ∆ b = a × a + b × b -a × b, the value of (-3) ∆ 2 is 19
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