# Prepare a continuous grouped frequency distribution from the following data:

Mid-point Frequency

5 4

15 8

25 13

35 12

45 6

Also find the size of class intervals.

**Solution:**

Difference between two mid points is 15-5 i.e 10

It depicts that the width of class interval is 10

Consider a as the lower limit of the first class interval

So the upper limit = a + 10

Mid class of the first class interval = 5

We know that

Mid value = (Lower limit + Upper limit)/2

Substituting the values

5 = (a + a + 10)/2

By further calculation

5 = (2a + 10)/2

2a + 10 = 10

So we get

2a = 0

a = 0

First class interval is 0-10

The continuous grouped __frequency distribution__ table is

Mid-point | Class Interval | Frequency |

5 | 0-10 | 4 |

15 | 10-20 | 8 |

25 | 20-30 | 13 |

35 | 30-40 | 12 |

45 | 40-50 | 6 |

Therefore, the size of the class interval is 10.

**✦ Try This: **The scores (out of 100) obtained by 24 students in a mathematics test are as follows: 62, 40, 82, 56, 40, 79, 84, 42, 42, 10, 54, 34, 25, 78, 96, 84, 60, 52, 55, 20, 57, 50, 24, 56. Represent this data in the form of a frequency distribution.

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.3 Problem 4**

## Prepare a continuous grouped frequency distribution from the following data: Mid-point Frequency 5 4 15 8 25 13 35 12 45 6. Also find the size of class intervals.

**Summary:**

A continuous grouped frequency distribution is mentioned above. The size of the class intervals is 10

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