# The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower

**Solution:**

We have to find the height of the tower.

Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC.

In ΔABC, trigonometric ratio involving AB, BC and ∠C is tan θ.

tan C = AB/BC

tan 30° = AB/30

1/√3 = AB/30

AB = 30/√3

= (30 × √3) / (√3 × √3)

= (30√3)/3

= 10√3

Height of tower AB = 10√3 m.

**☛ Check: **NCERT Solutions Class 10 Maths Chapter 9

**Video Solution:**

## The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower

Maths NCERT Solutions Class 10 Chapter 9 Exercise 9.1 Question 4

**Summary:**

If the angle of elevation of the top of a tower from a point on the ground, which is 30m away from the foot of the tower, is 30°, then the height of the tower is 10√3 m.

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