The factorisation of 4x² + 8x + 3 is
a. (x + 1) (x + 3)
b. (2x + 1) (2x + 3)
c. (2x + 2) (2x + 5)
d. (2x -1) (2x -3)
Solution:
It is given that
4x² + 8x + 3
= 4x² + 6x + 2x + 3
Taking out the common terms
= 2x( 2x + 3) + 1 (2x + 3)
So we get
= (2x + 3) (2x + 1)
Therefore, the factorisation is (2x + 3) (2x + 1).
✦ Try This: The factorisation of 2x² + 7x + 6 is
It is given that
2x² + 7x + 6
By splitting the middle term
= 2x² + 4x + 3x + 6
Taking out the common terms
= 2x (x + 2) + 3 (x + 2)
So we get
= (2x + 3) (x + 2)
Therefore, the factorisation is (2x + 3) (x + 2).
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.1 Problem 16
The factorisation of 4x² + 8x + 3 is a. (x + 1) (x + 3), b. (2x + 1) (2x + 3), c. (2x + 2) (2x + 5), d. (2x - 1) (2x - 3)
Summary:
The process of finding two or more expressions whose product is the given expression is known as the factorization of algebraic expressions. The factorisation of 4x² + 8x + 3 is (2x + 3) (2x + 1)
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