# The factorisation of 4x² + 8x + 3 is

a. (x + 1) (x + 3)

b. (2x + 1) (2x + 3)

c. (2x + 2) (2x + 5)

d. (2x -1) (2x -3)

**Solution:**

It is given that

4x² + 8x + 3

= 4x² + 6x + 2x + 3

Taking out the common terms

= 2x( 2x + 3) + 1 (2x + 3)

So we get

= (2x + 3) (2x + 1)

Therefore, the factorisation is (2x + 3) (2x + 1).

**✦ Try This: **The factorisation of 2x² + 7x + 6 is

It is given that

2x² + 7x + 6

By splitting the middle term

= 2x² + 4x + 3x + 6

Taking out the common terms

= 2x (x + 2) + 3 (x + 2)

So we get

= (2x + 3) (x + 2)

Therefore, the factorisation is (2x + 3) (x + 2).

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.1 Problem 16**

## The factorisation of 4x² + 8x + 3 is a. (x + 1) (x + 3), b. (2x + 1) (2x + 3), c. (2x + 2) (2x + 5), d. (2x - 1) (2x - 3)

**Summary:**

The process of finding two or more expressions whose product is the given expression is known as the factorization of algebraic expressions. The factorisation of 4x² + 8x + 3 is (2x + 3) (2x + 1)

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