Find an equation for the nth term of the arithmetic sequence. a19 = -58, a21 = -164
Solution:
It is given that
a19 = -58 and a21 = -164
We know that
an = a1 + d(n - 1)
It can be written as
-58 = a1 + d(19 - 1)
-58 = a1 + 18d ------- (1)
-164 = a1 + d(21 - 1)
-164 = a1 + d ------ (2)
Now multiply equation (1) by -1
58 = -a1 - 18d
-164 = a1 + 20d
By adding both equation ,we get
-106 = 2d
d = -53
Substituting the d value in either of the equations
-58 = a1 + -53(18)
-58 = a1 - 954
a1 = -58 + 954
So we get,
a1 = 896
The equation for nth term is
an = 896 - 53(n - 1)
Therefore, the equation for the nth term is an = 896 - 53(n - 1).
Find an equation for the nth term of the arithmetic sequence. a19 = -58, a21 = -164
Summary:
The equation for the nth term of the arithmetic sequence when a19 = -58, a21 = -164 is an = 896 - 53(n - 1).
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