# Find the area of a regular hexagon with a 48-inch perimeter.

**Solution:**

An equilateral triangle is a regular polygon with 3 equal sides with each angle equal to 60°.

The area of a regular hexagon is

A = (3√3)/2 × s^{2}, where s is the side length

The 6-sided figure will have a side length that is 1/6 of the perimeter.

S = (48 in)/6 = 8 in

A = (3√3)/2 × (8 in)^{2} = 96√3 in^{2}

Therefore, the area of a regular hexagon 48-inch perimeter is A = 96√3 sq. in

## Find the area of a regular hexagon with a 48-inch perimeter.

**Symmetry:**

The area of a regular hexagon with the given measurement 48-inch perimeter A = 96√3 sq. in

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