Given that f(x) = 6x + 2 and g(x) = the quantity of 2x plus 4 divided by 5, solve for g(f(1))
1, 3, 4, 8

Solution:

It is given that function

f(x) = 6x + 2

g(x) = (2x + 4)/5

We should find g(f(1))

g(f(x)) = g(6x + 2)

So we get

g(f(x)) = (2(6x + 2) + 4)/5

= (12x + 4 + 4)/5

= (12x + 8)/5

In g(f(x)) substitute x as 1

g(f(1)) = (12 (1) + 8)/5

= (12 + 8)/5

= 20/5

= 4

Therefore, g(f(1)) is 4.

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Given that f(x) = 6x + 2 and g(x) = the quantity of 2x plus 4 divided by 5, solve for g(f(1))

Summary:

Given that f(x) = 6x + 2 and g(x) = the quantity of 2x plus 4 divided by 5, g(f(1)) is 4.