# Given the function f(x) = 2x, find the value of f^{-1}(32).

**Solution:**

Inverse function is represented by f^{-1} with regards to the original function f and the domain of the original function becomes the range of inverse function and the range of the given function becomes the domain of the

inverse function.

Given __function__:

f(x) = 2x

A function is a relation from a non-empty set B such that the domain of a function is A and no two distinct ordered pairs in f have the same first element.

let f(x) = y = 2x

x = y/2

x = f^{-1}(y)

f^{-1}(32) = 32/2 = 16

## Given the function f(x) = 2x, find the value of f^{-1}(32).

**Summary:**

Given the function f(x) = 2x,the value of f^{-1}(32) is 16.

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