# If A and B are independent events with P(A) = 0.2 and P(B) = 0.6, then P(A ∪ B) is?

**Solution:**

P(A) = 0.2

P(B) = 0.6

As A and B are independent events

P (A ∩ B) = P(A) × P(B)

Substituting the values

P (A ∩ B) = 0.2 × 0.6

P (A ∩ B) = 0.12

We know that

P(A ∪ B) = P(A) + P(B) - P (A ∩ B)

Substituting the values

P(A ∪ B) = 0.2 + 0.6 - 0.12

So we get

P(A ∪ B) = 0.68

Therefore, P(A ∪ B) is 0.68.

## If A and B are independent events with P(A) = 0.2 and P(B) = 0.6, then P(A ∪ B) is?

**Summary:**

If A and B are independent events with P(A) = 0.2 and P(B) = 0.6, then P(A ∪ B) is 0.68.