Marcus needs to rewrite f(x) = x² + 6x + 4 in vertex form. What is the answer?

Solution:

Given f(x) = x² + 6x + 4

This is an equation of the parabola. The vertex is at (h,k)

The vertex form of the parabola is a(x-h)² +k

f(x) = x² + 6x + 4 +5 -5

= x² + 6x +9 -5

= ( x² + 2(3)x + 32) -5

= (x+3)² -5

= 1(x- (-3))² -5

f(x) = 1(x- (-3))² -5. This is of the vertex standard equation a(x-h)² +k.

Marcus needs to rewrite f(x) = f(x) = x² + 6x + 4 in vertex form. What is the answer?

Summary:

Marcus needs to rewrite f(x) = x² + 6x + 4 in vertex form. The answer is 1(x- (-3)²) -5.