Solve the triangle. A = 32°, a = 19, b = 14

Solution:

Given A = 32°, a = 19, b = 14

According to the laws of sines

SinA/a = SinB/b

sin32/ 19 = SinB / 14

0.52/19 = Sin B /14

sin B = 14 × 0.027

sin B = 0.3892

B = sin^-1(0.38)

B = 22.90°

we know that the sum of all angles of a triangle is 180 degrees.

A + B + C = 180°

32° + 22.90° + 0 = 180°

C = 180 - 54.90

C = 125.09°

Consider sin A/a = sinC/c

sin32 /19 = sin(125.09)/c

0.027 = 0.81/c

c = 0.81/0.27

c = 29.42

Hence, A = 32°, B = 22.90°, C = 125.09°

a = 19, b = 14, c = 29.42

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Solve the triangle. A = 32°, a = 19, b = 14

Summary:

By solving the triangle, we get, A = 32°, B = 22.90°, C = 125.09°, a = 19, b = 14, c = 29.42