# What are the solutions of 2x^{2} + 16x + 50 = 0?

**Solution:**

Given quadratic equation is

2x^{2} + 16x + 50 = 0

This is the quadratic equation, so we use quadratic formula to find the roots

x = -b ± √(b^{2} - 4ac) / 2a

Here a = 2; b = 16; c = 50

x = -16 ± √(16^{2} - 4(2)(50)) / 2(2)

x = -16 ± √(256 - 400) / 4

x = -16 ± √ -144 /4

x = -4 ± 3i

## What are the solutions of 2x^{2} + 16x + 50 = 0?

**Summary:**

The solutions of 2x^{2} + 16x + 50 = 0 are -4 ± 3i.

Math worksheets and

visual curriculum

visual curriculum