# What is the 50th term of the sequence that begins −4, 2, 8, 14, ...?

An arithmetic progression is a sequence in which the difference between a pair of consecutive numbers is equal.

## Answer: The 50th term of the sequence is 290.

Let's solve for the 50^{th} term of the sequence.

**Explanation:**

The given sequence is −4, 2, 8, 14, ...

It is in arithmetic progression as the difference between all consecutive terms is 6.

Let a be the first term and d be the common difference.

Therefore, a = - 4 and d = 6

For 50^{th} term, a_{50} = a + (n - 1) d

= - 4 + (50 - 1) × 6

= - 4 + 49 × 6

= - 4 + 294

= 290