# What is the logarithmic form of the equation e^{2x} ≈ 1732?

**Solution:**

Given the equation e^{2x} ≈ 1732

This is in exponential form.

To convert this to the logarithmic form, use this formula:

If a^{b} = x then log_{a}x = b

The logarithm base (e) 1732 = 2x

⇒Log_{e}1732 = 2x

## What is the logarithmic form of the equation e^{2x} ≈ 1732?

**Summary:**

The logarithmic form of the equation e^{2x} ≈ 1732 is log_{e}1732 = 2x.

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