# What is the solution to the equation 5/(3b^{3} -2b^{2} - 5) = 2/(b^{3} - 2)?

b = -4 and b = 0, b = -4, b = 0 and b = 4, b = 4

**Solution: **

Given equation is 5/(3b^{3} -2b^{2} - 5) = 2/(b^{3} - 2)

⇒ By Cross multiplication we get,

⇒ 5b^{3 }- 10 = 6b^{3} - 4b^{2} - 10

⇒ 5b^{3} - 6b^{3} = -4b^{2}

⇒ -b^{3} = -4b^{2}

⇒ b^{3} - 4b^{2} = 0

⇒ b^{2}(b - 4) = 0

⇒ b^{2} = 0 and b - 4 = 0

⇒ So we get b = 0 and b = 4

## What is the solution to the equation 5/(3b^{3} -2b^{2} - 5) = 2/(b^{3} - 2)?

**Summary: **

The solution to the equation 5/(3b^{3} -2b^{2} - 5) = 2/(b^{3} - 2) are b = 0 and b = 4.

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