# What is the sum of the first 30 terms of this arithmetic sequence? 6, 13, 20, 27, 34, …

**Solution:**

It is given that,

a = 6 and d = 7,

We have to find the sum of first 30 terms,

Then,

Sn = n/2 [2a + (n-1)d]

Substituting the values

S_{30} = 30/2 [ 2 x 6 + (30 - 1) x 7 ]

= 15 [ 12 + 29 x 7 ]

By further calculation

= 15 [ 12 + 203 ]

= 15 x 215

= 3225

Therefore, the sum of the first 30 terms is 3225.

## What is the sum of the first 30 terms of this arithmetic sequence? 6, 13, 20, 27, 34, …

**Summary:**

The sum of the first 30 terms of this arithmetic sequence 6, 13, 20, 27, 34, … is 3225.