Which is a zero of the quadratic function f(x) = 4x² + 24x + 11?
x = -9.25, x = -5.5, x = 0.5, x = 3.25

Solution:

The given quadratic function is

f(x) = 4x² + 24x + 11

The formula used to solve the quadratic equation is

x = [-b ± √b² - 4ac]/ 2a

The values here are

a = 4, b = 24, c = 11

Substituting it we get

x = [-24 ± √(24)² - 4(4)(11)]/ 2(4)

x = [-24 ± √576 - 176]/ 8

By further calculation

x = [-24 ± √400]/8

x = [-24 ± 20]/8

So we get

x = (-24 + 20)/8 = -4/8 = -0.5

x = (-24 - 20)/8 = -44/8 = -22/4 = -11/4

Therefore, the zero of the quadratic function is x = -0.5

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Which is a zero of the quadratic function f(x) = 4x² + 24x + 11?

Summary:

The zero of the quadratic function f(x) = 4x² + 24x + 11 is x = -0.5