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# After rationalising the denominator of 7/(3√3 - 2√2), we get the denominator as

a. 13

b. 19

c. 5

d. 35

**Solution:**

Given

7/(3√3 - 2√2)

Let us multiply both __numerator__ and __denominator__ by 3√3 + 2√2

= 7/(3√3 - 2√2) × (3√3 + 2√2)/ (3√3 + 2√2)

Using the __algebraic identity__ (a + b) (a - b) = a² - b²

= 7(3√3 + 2√2)/ (3√3)² - (2√2)²

= 7(3√3 + 2√2)/ (27 - 8)

By further calculation

= 7(3√3 + 2√2)/19

Therefore, we get the denominator as 19.

**✦ Try This: **After rationalising the denominator of 9/(5√5 - 3√3), we get the denominator as

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 1

**NCERT Exemplar Class 9 Maths Exercise 1.1 Problem 14**

## After rationalising the denominator of 7/(3√3 -2√2), we get the denominator as a. 13, b. 19, c. 5, d. 35

**Summary**:

Rationalizing the denominator means the process of moving a root, for instance, a cube root or a square root from the bottom of a fraction (denominator) to the top of the fraction (numerator). After rationalising the denominator of 7/(3√3 - 2√2), we get the denominator as 19

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