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# Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. Find how much moulding will be needed for bed room 2

**Solution:**

The figure represents the plan for a house.

An architect wants to install decorative moulding around the ceilings in all the rooms.

The decorative moulding costs ₹500/metre.

We have to find the moulding needed for bed room 2.

From the plan we observe that the bed room 2 is in rectangular shape.

__Perimeter of rectangle__ = 2(length + breadth)

Length = 3.04 m

Breadth = 2.43 m

Perimeter = 2(3.04 + 2.43)

= 2(5.47)

= 10.94 m

Therefore, the moulding needed for bed room 2 is 10.94 m.

**✦ Try This: **A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs 23.25. What will be the cost to cover the floor with these tiles?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 126 (a) (v)**

## Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. Find how much moulding will be needed for bed room 2

**Summary:**

Architects design many types of buildings. They draw plans for houses, such as the plan shown in Fig. 9.68: An architect wants to install decorative moulding around the ceilings in all the rooms. The decorative moulding costs ₹500/metre. 10.94 m of moulding will be needed for bed room 2.

**☛ Related Questions:**

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