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# Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm

**Solution:**

To construct a right-angled ΔPQR, where ∠Q = 90°, QR = 8cm, and PR = 10cm, draw a rough sketch for your reference and mark the measures.

Remember to mark the right angle and follow the steps given below.

**Steps of construction:**

- Draw a line segment QR of length 8 cm.
- At Q, draw QX perpendicular QR.
- With R as the center, draw an arc of radius 10cm which should intersect QX at point P.
- Join P and R.
- ΔPQR is the required triangle.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 10

**Video Solution:**

## Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.5 Question 1

**Summary:**

A right angled ∆PQR is constructed, where m∠Q = 90°, QR = 8cm and PR = 10 cm.

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