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# Draw ∠POQ of measure 75° and find its line of symmetry

**Solution:**

We will be using the concept of angles and lines of symmetry.

Steps of construction:

Step I: On a plane sheet, draw a line segment PQ

Step II: With Q as a center, draw a substantial arc to cut PQ at R.

Step III: Take R as a center and with the same radius as before, mark S and T on the former arc.

Step IV: Take S and T as the center, with the same radius as before, draw an arc such that they intersect each other at U.

Step V: Join the points QU such that ∠PQU = 90°.

Step VI: Take S and W as centers, draw two arcs of the same radius which meet each other at Q.

Step VII: Join the points Q and O such that ∠PQO = 75°.

Step VIII: Bisect ∠PQO at point V where QV bisects the angle.

Therefore, ∠PQV = ∠VQO

Hence, QV is the line of symmetry for ∠PQO.

NCERT Solutions for Class 6 Maths Chapter 14 Exercise 14.6 Question 1

## Draw ∠POQ of measure 75° and find its line of symmetry

**Summary:**

We have drawn ∠POQ of measure 75° and QV its line of symmetry.

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