# Find the coordinates of the points which divide the line segment joining A (- 2, 2) and B (2, 8) into four equal parts

**Solution:**

The coordinates of the point P(x, y) which divides the line segment joining the points A(x₁, y₁) and B(x₂, y₂), internally, in the ratio m₁: m₂ is given by the section formula.

By observation, points P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts.

Point P divides the line segment AQ into two equal parts.

Therefore, AP : PB is 1 : 3

Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n]

Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2)

Point Q divides the line segment AB into two equal parts

Using mid point formula,

Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5)

Point R divides the line segment BQ into two equal parts

Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2)

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 7

**Video Solution:**

## Find the coordinates of the points which divide the line segment joining A (- 2, 2) and B (2, 8) into four equal parts

NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.2 Question 9

**Summary:**

The coordinates of the points which divide the line segment joining A (- 2, 2) and B (2, 8) into four equal parts is (- 1, 7/2), (0, 5), and (1, 13/2).

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