# If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5? Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum Frequency

2 14

3 30

4 42

5 55

6 72

7 75

8 70

9 53

10 46

11 28

12 15

**Solution:**

Given, two dice are thrown simultaneously 500 times.

Each time the sum of the two numbers appearing on their tops is noted and recorded.

The table represents the sum of the numbers on the top of the dice and their frequencies

We have to determine the probability of getting a sum less than or equal to 5, if the dice are thrown once more.

__Probability__ of an event = Number of trials in which the event has happened / Total number of trials

From the given table,

Number of times we get a sum less than or equal to 5 = 14 + 30 + 42 + 55

= 44 + 42 + 55

= 86 + 55

= 141

So, the number of trials in which the event has happened = 141

Total number trails = 500

Probability of getting a sum less than or equal to 5 = 141/500

= 0.282

Therefore, the required probability is 0.282

**✦ Try This: **Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is less than 12.

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.3 Problem 17(iii)**

## If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5? Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency 2 14 3 30 4 42 5 55 6 72 7 75 8 70 9 53 10 46 11 28 12 15

**Summary:**

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the table. If the dice are thrown once more, the probability of getting a sum less than or equal to 5 is 0.282

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