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# If the dice are thrown once more, what is the probability of getting a sum between 8 and 12? Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum Frequency

2 14

3 30

4 42

5 55

6 72

7 75

8 70

9 53

10 46

11 28

12 15

**Solution:**

Given, two dice are thrown simultaneously 500 times.

Each time the sum of the two numbers appearing on their tops is noted and recorded.

The table represents the sum of the numbers on the top of the dice and their frequencies

We have to determine the __probability__ of getting a sum between 8 and 12, if the dice are thrown once more.

Probability of an event = Number of trials in which the event has happened / Total number of trials

From the given table,

Number of time we get a sum between 8 and 12 = 53 + 46 + 28

= 99 + 28

= 127

So, number of trials in which the event has happened = 127

Total number trails = 500

Probability of getting a sum between 8 and 12 = 127/500

= 0.254

Therefore, the required probability is 0.254

**✦ Try This: **Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is less than or equal to 12.

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.3 Problem 17(iv)**

## If the dice are thrown once more, what is the probability of getting a sum between 8 and 12? Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency 2 14 3 30 4 42 5 55 6 72 7 75 8 70 9 53 10 46 11 28 12 15

**Summary:**

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the table. If the dice are thrown once more, the probability of getting a sum between 8 and 12 is 0.254

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