PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
It is given in the question that PQR is a right-angled triangle and it is right-angled at P.
So, we can apply the Pythagoras theorem here.
If it is right-angled at P then the side opposite to P will be the hypotenuse of the triangle i.e. QR and the other sides are given as PQ = 10 cm and PR = 24 cm.
Now, by applying the Pythagoras theorem i.e. in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides, we can find QR.
Given, PQ = 10 cm, PR = 24 cm and QR =?
By applying Pythagoras theorem in triangle PQR, we get (Hypotenuse)2 = (Perpendicular)2 + (Base)2
(QR)2 = (PQ)2 + (PR)2
(QR)2 = (10)2 + (24)2
(QR)2 = 100 + 576
(QR)2 = 676
QR = 26 cm
Thus, QR is equal to 26 cm.
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR
NCERT Solutions for Class 7 Maths Chapter 6 Exercise 6.5 Question 1
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, QR is equal to 26 cm
☛ Related Questions:
- Abc Is A Triangle Right Angled At C If Ab 25 Cm And Ac 7 Cm Find Bc
- A 15 M Long Ladder Reached A Window 12 M High From The Ground On Placing It Against A Wall At A Distance A Find The Distance Of The Foot Of The Ladder From The Wall
- Which Of The Following Can Be The Sides Of A Right Triangle I 25 Cm 65 Cm 6 Cm Ii 2 Cm 2 Cm 5 Cm Iii 15 Cm 2cm 25 Cm
- A Tree Is Broken At A Height Of 5 M From The Ground And Its Top Touches The Ground At 12 M From The Base Of The Tree Find The Original Height Of The Tree