# PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

**Solution:**

It is given in the question that PQR is a right-angled triangle and it is right-angled at P.

So, we can apply the Pythagoras theorem here.

If it is right-angled at P then the side opposite to P will be the hypotenuse of the triangle i.e. QR and the other sides are given as PQ = 10 cm and PR = 24 cm.

Now, by applying the Pythagoras theorem i.e. in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides, we can find QR.

Given, PQ = 10 cm, PR = 24 cm and QR =?

By applying Pythagoras theorem in triangle PQR, we get (Hypotenuse)^{2 }= (Perpendicular)^{2 }+ (Base)^{2}

(QR)^{2 }= (PQ)^{2 }+ (PR)^{2}

(QR)^{2} = (10)^{2 }+ (24)^{2}

(QR)^{2 }= 100 + 576

(QR)^{2 }= 676

QR = 26 cm

Thus, QR is equal to 26 cm.

**ā Check: **NCERT Solutions for Class 7 Maths Chapter 6

**Video Solution:**

## PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR

NCERT Solutions for Class 7 Maths Chapter 6 Exercise 6.5 Question 1

**Summary:**

PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, QR is equal to 26 cm

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