Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4

Solution:

Given: x varies inversely as y, and x = 132 when y = 4

We have to find x when y = 32

X varies inversely with y if there will be a constant of proportionality k such that :

⇒ (x)(y) = k ----(1)

⇒ Put the value of x and y in eq(1) to find the value of k

⇒ (132)(4) = k

Therefore, k = 528

We get

⇒ (x)(y) = 528

x when y = 32

⇒ (x)(32) = 528

⇒ x = 528/32

⇒ x = 16.5

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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4

Summary:

When x varies inversely with y, so when y = 32 the value of x will be 16.5