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# How many solutions does this linear system have? y = x + 2 and 6x - 4y = -10

**Solution:**

Given, y = x + 2 ------------- (1)

6x - 4y = -10 ----------------- (2)

Substituting (1) in (2)

6x - 4(x + 2) = -10

6x - 4x - 8 = -10

Grouping of common terms,

6x - 4x = -10 + 8

2x = -2

x = -1

Put the value of x = -1 in (1)

y = -1 + 2

y = 1

Therefore, the solution is x = -1 and y = 1.

Hence, it has one solution.

## How many solutions does this linear system have? y = x + 2 and 6x - 4y = -10

**Summary:**

The linear system of equations y = x + 1 and 6x - 4y = -10 have one solution.i.e. x = -1 and y = 1.

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